8x^2+38x+17=0

Solution for 8x^2+38x+17=0 equation:

8x^2+38x+17=0

a = 8; b = 38; c = +17;
Δ = b2-4ac
Δ = 382-4·8·17
Δ = 900
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{900}=30$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(38)-30}{2*8}=\frac{-68}{16}
=-4+1/4
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(38)+30}{2*8}=\frac{-8}{16}
=-1/2
$